1a4e464d5ef79a587fad3e439f56400716665fcb
`=` was missing from the Pratt table, causing `a = b;` to fail with "expected `;`, found `=`". Assignment is now BinaryOp::Assign with binding power (2, 2) — lowest precedence, right-associative — so `a = b = c` parses as `a = (b = c)`.
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